Accuplacer Practice Test 2025 – 400 Free Practice Questions to Pass the Exam

Image Description

Question: 1 / 400

If θ is an acute angle and sin θ = 1/2, then cos θ =

-1

0

1/2

√3/2

When considering the relationship between the sine and cosine functions in a right triangle, both functions can be derived from the same angle. Since \( \sin \theta = \frac{1}{2} \) and \( \theta \) is an acute angle, we can recall the sine values of special angles.

The sine of \( 30^\circ \) (or \( \frac{\pi}{6} \) radians) is \( \frac{1}{2} \). In a right triangle corresponding to this angle, the cosine can also be found. The cosine function measures the ratio of the length of the adjacent side to the hypotenuse. For an angle of \( 30^\circ \), using the properties of a 30-60-90 triangle, the length of the adjacent side (the side opposite the \( 60^\circ \) angle) is \( \sqrt{3} \) when the hypotenuse is \( 2 \). Therefore,

\[

\cos 30^\circ = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{\sqrt{3}}{2}.

\]

Thus, with \( \sin \theta = \frac{1

Get further explanation with Examzify DeepDiveBeta
Next Question

Report this question

Download Accuplacer Practice Test PDF Study Guide
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy